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Tardigrade
Question
Chemistry
The van der Waals equation for one mole of a real gas at low pressure is
Q. The van der Waals equation for one mole of a real gas at low pressure is
1934
231
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A
P
V
=
RT
−
V
a
47%
B
P
V
=
P
b
+
RT
23%
C
P
V
=
RT
−
P
b
11%
D
P
V
=
RT
+
V
a
19%
Solution:
(
P
+
V
2
a
)
(
V
−
b
)
=
RT
At low
P
,
V
is large
V
−
b
≈
V
(
P
+
V
2
a
)
(
V
)
=
RT
⇒
P
V
+
V
a
=
RT
P
V
=
RT
−
V
a