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Tardigrade
Question
Mathematics
The values of x at the stationary points of f(x)=x3+3 x2-2 are
Q. The values of
x
at the stationary points of
f
(
x
)
=
x
3
+
3
x
2
−
2
are
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A
0,2
B
1,2
C
0,-2
D
1,1
Solution:
Let
y
=
f
(
x
)
=
x
3
+
3
x
2
−
2
d
x
d
y
=
3
x
2
+
6
x
⇒
d
x
2
d
2
y
=
6
x
+
6
For stationary points
d
x
d
y
=
0
⇒
3
x
(
x
+
2
)
=
0
⇒
x
=
0
,
−
2