The value of the integral ∫ ( sin ( ln (2+2 x))/x+1) d x is

Question

The value of the integral ∫ ( sin ( ln (2+2 x))/x+1) d x is (A) - cos ln (2 x+2)+C (B)  ln ( sin (2/ x +1))+ C (C)  cos ((2/x+1))+C (D)  sin ((2/x+1))+C

Tardigrade Admin · Accepted Answer

ln 2(1+x)=t ; (1/(1+x)) d x=d t

Q. The value of the integral $\int \frac{s i n ( l n ( 2 + 2 x ))}{x + 1} d x$ is

$- cos ln (2 x + 2) + C$

$ln (sin \frac{2}{x + 1}) + C$

$cos (\frac{2}{x + 1}) + C$

$sin (\frac{2}{x + 1}) + C$

$ln 2 (1 + x) = t; \frac{1}{( 1 + x )} d x = d t$

Q. The value of the integral ∫x+1sin(ln(2+2x))​dx is

−cosln(2x+2)+C

ln(sinx+12​)+C

cos(x+12​)+C

sin(x+12​)+C

ln2(1+x)=t;(1+x)1​dx=dt

Q. The value of the integral $\int \frac{s i n ( l n ( 2 + 2 x ))}{x + 1} d x$ is

$- cos ln (2 x + 2) + C$

$ln (sin \frac{2}{x + 1}) + C$

$cos (\frac{2}{x + 1}) + C$

$sin (\frac{2}{x + 1}) + C$

$ln 2 (1 + x) = t; \frac{1}{( 1 + x )} d x = d t$