Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
The value of the expression ( textcosec 50°+√3 sec 50°) is equal to
Q. The value of the expression
(
cosec
5
0
∘
+
3
sec
5
0
∘
)
is equal to
215
180
Trigonometric Functions
Report Error
Answer:
4
Solution:
y
=
2
[
2
s
i
n
5
0
∘
1
+
2
c
o
s
5
0
∘
3
]
=
2
[
s
i
n
5
0
∘
c
o
s
6
0
∘
+
c
o
s
5
0
∘
s
i
n
6
0
∘
]
=
4
×
s
i
n
10
0
∘
c
o
s
1
0
∘
=
4