The value of the equilibrium constant for the reaction, N2+2 O2 leftharpoons 2 N O2 is 100 . The equilibrium constant for the reaction N O2 leftharpoons (1/2) N2+O2 will be

Question

The value of the equilibrium constant for the reaction, N2+2 O2 leftharpoons 2 N O2 is 100 . The equilibrium constant for the reaction N O2 leftharpoons (1/2) N2+O2 will be (A) 100 (B) 0.010 (C) 0.10 (D) 1000

Tardigrade Admin · Accepted Answer

For the reaction, N 2+2 O 2 2 NO 2 Kc=([N O2]2/[N2][O2]2)=100, ... (i) For the reaction, NO 2 (1/2) N 2+ O 2 Kc=([N2]1 / 2[O2]/[N O2]) or (Kc)2=([N2][O2]/[N O2]2) =(1/100) ( from equation (i) ] ∴ Kc=√(1/100)=(1/10)=0.10

Q. The value of the equilibrium constant for the reaction, N2​+2O2​⇌2NO2​ is 100 . The equilibrium constant for the reaction NO2​⇌21​N2​+O2​ will be

100

0.010

0.10

1000

For the reaction, N2​+2O2​2NO2​ Kc​=[N2​][O2​]2[NO2​]2​=100,... (i) For the reaction, NO2​21​N2​+O2​ Kc​=[NO2​][N2​]1/2[O2​]​ or (Kc​)2=[NO2​]2[N2​][O2​]​ =1001​ ( from equation (i) ] ∴Kc​=1001​​=101​=0.10

Q. The value of the equilibrium constant for the reaction, $N_{2} + 2 O_{2} ⇌ 2 N O_{2}$ is $100$ . The equilibrium constant for the reaction $N O_{2} ⇌ \frac{1}{2} N_{2} + O_{2}$ will be