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Question
Mathematics
The value of the determinant |a&a+2b&a+4b a+2b&a+4b&a+6b a+4b&a+6b&a+8b| is equal to
Q. The value of the determinant
∣
∣
a
a
+
2
b
a
+
4
b
a
+
2
b
a
+
4
b
a
+
6
b
a
+
4
b
a
+
6
b
a
+
8
b
∣
∣
is equal to
2541
196
Determinants
Report Error
A
3
a
+
7
b
26%
B
2b
15%
C
0
48%
D
none of these.
10%
Solution:
Operating
R
2
→
R
2
−
R
1
and
R
3
→
R
3
−
R
2
,
we get
∣
∣
a
2
b
2
b
a
+
2
b
2
b
2
b
a
+
4
b
2
b
2
b
∣
∣
which is certainly 0 as
R
2
=
R
3
.