The value of the determinant |265&240&219 240&225&198 219&198&181| is

Question

The value of the determinant |265&240&219 240&225&198 219&198&181| is (A) 1000 (B) 779 (C) 679 (D) 0

Tardigrade Admin · Accepted Answer

Applying C1 -C2 and C2 -C3, we get Det. = |25&21&219 15&27&198 21&17&181| = |4&21&9 -12&27&-72 4&17&11| [ textby C1 -C2 , C3 - 10 C2] = |4&21&9 0&90&-45 0&-4&2| [ textBy R2 + 3R1 , R3 - R1] = 4 (180 - 180) = 0

Q. The value of the determinant $∣ ∣ 265240219240225198219198181 ∣ ∣$ is

1000

779

679

0

Applying $C_{1} - C_{2}$ and $C_{2} - C_{3},$ we get
Det. $= ∣ ∣ 251521212717219198181 ∣ ∣ = ∣ ∣ 4 - 12 4 212717 9 - 72 11 ∣ ∣$
$[by C_{1} - C_{2}, C_{3} - 10 C_{2}]$
$= ∣ ∣ 400 2190 - 4 9 - 45 2 ∣ ∣ [By R_{2} + 3 R_{1}, R_{3} - R_{1}]$
$= 4 (180 - 180) = 0$

Q. The value of the determinant ∣∣​265240219​240225198​219198181​∣∣​ is

1000

779

679

0

Applying C1​−C2​ and C2​−C3​, we get Det.=∣∣​251521​212717​219198181​∣∣​=∣∣​4−124​212717​9−7211​∣∣​ [byC1​−C2​,C3​−10C2​] =∣∣​400​2190−4​9−452​∣∣​[ByR2​+3R1​,R3​−R1​] =4(180−180)=0

Q. The value of the determinant $∣ ∣ 265240219240225198219198181 ∣ ∣$ is

Applying $C_{1} - C_{2}$ and $C_{2} - C_{3},$ we get
Det. $= ∣ ∣ 251521212717219198181 ∣ ∣ = ∣ ∣ 4 - 12 4 212717 9 - 72 11 ∣ ∣$
$[by C_{1} - C_{2}, C_{3} - 10 C_{2}]$
$= ∣ ∣ 400 2190 - 4 9 - 45 2 ∣ ∣ [By R_{2} + 3 R_{1}, R_{3} - R_{1}]$
$= 4 (180 - 180) = 0$