Question

The value of the derivative of $|x-1|+|x-3|$at $x=2$ is

Answer 1

Answer: 0

Given : $f(x)=|x-1|+|x-3|$
At $x=2,|x-1|=x-1$
and $|x-3|=-x+3$
$\Rightarrow f(x)=x-1-x+3=2$
which is a constant function
$\Rightarrow f^{\prime }(2)=0$