The value of the currents I1, I2, and I3 flowing through the circuit given below is

Question

The value of the currents I1, I2, and I3 flowing through the circuit given below is (A) I1 = - 3A, I2 = 2A, I3 = -1A (B) I1 = 2A, I2 = -3A, I3 = -1A (C) I1 = 3A, I2 = -1A, I3 = -2A (D) I1 = 1A, I2 = -3A, I3 = -2A

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/1a94bb8f445f8bd03da728410ca5b7b2-.png" /> Applying Kirchoff's law 10-6 IB+14-4 IA=0 ...(loop 1) 24=6 IB+4 IA 12=3 IB+2 IA ...(i) IA=IB+IC (junction) 10-6 IB+2 IC=0 ...(loop 2) 10=6 IB-2 IC 10=6 IB-2(IA-IB) ...(ii) On solving Eqs. (i) and (ii), we get IB=2 A , IA=3 A , IC=1 A Now as per given circuit, I1=IB=2 A , I2=-IA=-3 A I3=-IC=-1 A

Q. The value of the currents $I_{1}, I_{2},$ and $I_{3}$ flowing through the circuit given below is

$I_{1} = - 3 A, I_{2} = 2 A, I_{3} = - 1 A$

$I_{1} = 2 A, I_{2} = - 3 A, I_{3} = - 1 A$

$I_{1} = 3 A, I_{2} = - 1 A, I_{3} = - 2 A$

$I_{1} = 1 A, I_{2} = - 3 A, I_{3} = - 2 A$

$I_{1} = 2 A, I_{2} = - 1 A, I_{3} = - 3 A$

Q. The value of the currents I1​,I2​, and I3​ flowing through the circuit given below is

I1​=−3A,I2​=2A,I3​=−1A

I1​=2A,I2​=−3A,I3​=−1A

I1​=3A,I2​=−1A,I3​=−2A

I1​=1A,I2​=−3A,I3​=−2A