The value of the current I1, I2 and I3 flowing through the circuit given below is

Question

The value of the current I1, I2 and I3 flowing through the circuit given below is <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-iq3cf2zwdduwibrx.jpg" /> (A) I1=-3A, I2=2A, I3=-1A (B) I1=2A, I2=-3A, I3=-1A  (C) I1=3A, I2=-1A, I3=-2A (D) I1=1A, I2=-3A, I3=-2A

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/p-iq3cf2zwdduwgabd.jpg" /> Applying Kirchoff's law 10-6IB+14-4IA=0 ...(loop 1) 24=6IB+4IA 12=3IB+2IA .....(i) IA=IB+IC .....(junction) 10-6IB+2IC=0 .....(loop 2) 10=6IB-2IC 10=6IB-2(IA - IB) .....(ii) On solving Equations (i) and (ii), we get IB=2A, IA=3A, IC=1A Now as per given circuit, I1=IB=2A, I2=-IA=-3A I3=-IC= -1A

Q. The value of the current $I_{1}, I_{2}$ and $I_{3}$ flowing through the circuit given below is

$I_{1} = - 3 A, I_{2} = 2 A, I_{3} = - 1 A$

$I_{1} = 2 A, I_{2} = - 3 A, I_{3} = - 1 A$

$I_{1} = 3 A, I_{2} = - 1 A, I_{3} = - 2 A$

$I_{1} = 1 A, I_{2} = - 3 A, I_{3} = - 2 A$

Q. The value of the current I1​,I2​ and I3​ flowing through the circuit given below is

I1​=−3A,I2​=2A,I3​=−1A

I1​=2A,I2​=−3A,I3​=−1A

I1​=3A,I2​=−1A,I3​=−2A

I1​=1A,I2​=−3A,I3​=−2A

Q. The value of the current $I_{1}, I_{2}$ and $I_{3}$ flowing through the circuit given below is

$I_{1} = - 3 A, I_{2} = 2 A, I_{3} = - 1 A$

$I_{1} = 2 A, I_{2} = - 3 A, I_{3} = - 1 A$

$I_{1} = 3 A, I_{2} = - 1 A, I_{3} = - 2 A$

$I_{1} = 1 A, I_{2} = - 3 A, I_{3} = - 2 A$