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Tardigrade
Question
Mathematics
The value of tan15° + tan75° is equal to
Q. The value of tan
1
5
∘
+ tan
7
5
∘
is equal to
2453
222
KEAM
KEAM 2015
Trigonometric Functions
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A
2
3
0%
B
2
12%
C
2
−
3
0%
D
4
3
0%
E
4
0%
Solution:
tan
1
5
∘
+
tan
7
5
∘
=
3
+
1
3
−
1
+
3
−
1
3
+
1
[
∵
tan
1
5
∘
=
3
+
1
3
−
1
,
tan
7
5
∘
=
3
−
1
3
+
1
]
=
(
3
+
1
)
(
3
−
1
)
(
3
−
1
)
2
+
(
3
+
1
)
2
=
3
−
1
3
+
1
−
2
3
+
3
+
1
+
2
3
=
4