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Q. The value of tan$15^\circ$ + tan$75^\circ$ is equal to

KEAMKEAM 2015Trigonometric Functions

Solution:

$\tan 15^{\circ}+\tan 75^{\circ}$
$=\frac{\sqrt{3}-1}{\sqrt{3}+1}+\frac{\sqrt{3}+1}{\sqrt{3}-1}$
$\left[\because \tan 15^{\circ}=\frac{\sqrt{3}-1}{\sqrt{3}+1}, \tan 75^{\circ}=\frac{\sqrt{3}+1}{\sqrt{3}-1}\right]$
$=\frac{(\sqrt{3}-1)^{2}+(\sqrt{3}+1)^{2}}{(\sqrt{3}+1)(\sqrt{3}-1)}$
$=\frac{3+1-2 \sqrt{3}+3+1+2 \sqrt{3}}{3-1}=4$