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Tardigrade
Question
Mathematics
The value of tan 75°- cot 75° is
Q. The value of
tan
7
5
∘
−
cot
7
5
∘
is
187
209
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A
2
3
B
2
−
3
C
2
+
3
D
0
Solution:
tan
7
5
∘
−
cot
7
5
∘
=
c
o
s
7
5
∘
s
i
n
7
5
∘
−
s
i
n
7
5
∘
c
o
s
7
5
∘
=
s
i
n
7
5
∘
⋅
c
o
s
7
5
∘
s
i
n
2
7
5
∘
−
c
o
s
2
7
5
∘
=
s
i
n
15
0
∘
−
2
c
o
s
15
0
∘
=
s
i
n
(
90
+
6
0
∘
)
−
2
c
o
s
(
9
0
∘
+
6
0
∘
)
=
2
1
2
⋅
2
3
=
2
3