Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
The value of ( sin 210°)( sin 585°) is
Q. The value of
(
sin
21
0
∘
)
(
sin
58
5
∘
)
is
2300
199
AP EAMCET
AP EAMCET 2020
Report Error
A
2
2
1
B
2
2
−
1
C
3
1
D
3
−
1
Solution:
sin
21
0
∘
⋅
sin
58
5
∘
=
sin
(
18
0
∘
+
3
0
∘
)
⋅
sin
(
54
0
∘
+
4
5
∘
)
=
−
sin
3
0
∘
(
−
sin
4
5
∘
)
=
2
−
1
×
2
−
1
=
2
2
1