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Tardigrade
Question
Mathematics
The value of S=(5/12 ⋅ 42)+(11/42 ⋅ 72)+(17/72 ⋅ 102)+⋅s ∞ is
Q. The value of
S
=
1
2
⋅
4
2
5
+
4
2
⋅
7
2
11
+
7
2
⋅
1
0
2
17
+
⋯
∞
is
1620
213
Sequences and Series
Report Error
A
1
B
1/2
C
1/3
D
1/4
Solution:
S
=
1
2
⋅
4
2
5
+
4
2
⋅
7
2
11
+
7
2
⋅
1
0
2
17
+
⋯
∞
3
S
=
1
2
⋅
4
2
3
⋅
5
+
4
2
⋅
7
2
3
⋅
11
+
7
2
⋅
1
0
2
3
⋅
17
+
⋯
∞
⇒
3
S
=
1
2
⋅
4
2
(
4
−
1
)
(
4
+
1
)
+
4
2
⋅
7
2
(
7
−
4
)
(
7
+
4
)
+
7
2
⋅
1
0
2
(
10
−
7
)
(
10
+
7
)
+
⋯
∞
⇒
S
=
3
1