Question

The value of $\frac{{\log }_{3}5\times {\log }_{25}27\times {\log }_{49}7}{{\log }_{81}3}$ is

• A. 1
• B. 6
• C. $\frac{2}{3}$
• D. 3

Answer 1

Answer: (D)

$\frac{\left(\frac{\log 5}{\log 3}\times \frac{3\log 3}{2\log 5}\times \frac{\log 7}{2\log 7}\right)}{\left(\frac{\log 3}{4\log 3}\right)}$
$=3\left[\because {\log }_{a}b=\frac{\log b}{\log a}\right]$