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Question
Mathematics
The value of k(k ∈ R) such that textdet( textadj( textadj A))=16 where A=[k 1 2 0 -1 1 4 1 1], is equal to
Q. The value of
k
(
k
∈
R
)
such that
det
(
adj
(
adj
A
))
=
16
where
A
=
⎣
⎡
k
0
4
1
−
1
1
2
1
1
⎦
⎤
, is equal to
662
169
Report Error
A
5,7
B
2,7
C
5,2
D
5,3
Solution:
∣
A
∣
=
∣
∣
k
0
4
1
−
1
1
2
1
1
∣
∣
=
k
(
−
1
−
1
)
−
1
(
0
−
4
)
+
2
(
0
+
4
)
=
−
2
k
+
12
=
12
−
2
k
∣
adj
(
adj
A
)
∣
=
∣
A
∣
4
=
(
12
−
2
k
)
4
=
16
⇒
2
k
−
12
=
±
2
⇒
k
=
7
,
5