The value of Kc for the reaction: A + 3B2C at 400°C is 0.5. Calculate the value of KP

Question

The value of Kc for the reaction: A + 3B<=>2C at 400°C is 0.5. Calculate the value of KP (A) 1.64 × 10-4 (B) 1.64 × 10-6 (C) 1.64 × 10-5 (D) 1.64 × 10-3

Tardigrade Admin · Accepted Answer

Kp=Kc[RT]Δ ng Δ n=2-4=-2 T=673K, Kc=0.5, R=0.082 L. atm. mol-1 K-1 Kp=0.5×(0.082×673)-2 =1.64×10-4 atm.

Q. The value of $K_{c}$ for the reaction :
$A + 3 B 2 C$ at $40 0^{°} C$ is $0.5.$ Calculate the value of $K_{P}$

$1.64 \times 1 0^{- 4}$

$1.64 \times 1 0^{- 6}$

$1.64 \times 1 0^{- 5}$

$1.64 \times 1 0^{- 3}$

$K_{p} = K_{c} [RT]_{g}^{Δ n} Δ n = 2 - 4 = - 2$
$T = 673 K, K_{c} = 0.5,$
$R = 0.082 L . a t m . m o l^{- 1} K^{- 1}$
$K_{p} = 0.5 \times (0.082 \times 673)^{- 2} < b r / >= 1.64 \times 1 0^{- 4} a t m .$

Q. The value of Kc​ for the reaction : A+3B​2C at 400°C is 0.5. Calculate the value of KP​

1.64×10−4

1.64×10−6

1.64×10−5

1.64×10−3