Question

The value of $I$ in the figure shown below is

• A. 8A
• B. 21A
• C. 19A
• D. 4A

Answer 1

Answer: (B)

At junction A
$20=5+x$
$x=20-5=15A$
At junction $B$,
$4+x=y$
$4+15=y$
$y=19A$
At junction $C$
$=5=3+z$
$z=5-3=2A$
Now, network is shown by following diagram

At junction D
$I=19+2$
$I=21A$