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Physics
The value of I in the figure shown below is
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Q. The value of $I$ in the figure shown below is
KCET
KCET 2017
Current Electricity
A
8A
8%
B
21A
70%
C
19A
14%
D
4A
8%
Solution:
At junction A
$20 =5+x $
$x =20-5=15 \,A$
At junction $B$,
$4+x =y $
$4+15 =y $
$y =19 \,A$
At junction $C$
$=5=3+z$
$z=5-3=2 A$
Now, network is shown by following diagram
At junction D
$I=19+2$
$I=21 \,A$