The value of Henry's law constant for some gases at 293 K is given below. Arrange the gases in the increasing order of their solubility. He: 144.97 kbar, H2: 69.16 kbar, N2: 76.48 kbar, O2: 34.86 kbar

Question

The value of Henry's law constant for some gases at 293 K is given below. Arrange the gases in the increasing order of their solubility. He: 144.97 kbar, H2: 69.16 kbar, N2: 76.48 kbar, O2: 34.86 kbar (A) He < N2 < H2 < O2 (B) O2 < H2 < N2 < He (C) H2 < N2 < O2 < He (D) He < O2 < N2 < H2

Tardigrade Admin · Accepted Answer

Higher the value of KH , lower is the solubility of gas in the liquid. The correct order of solubility of these gases is as follows underset144.97H e < underset76.48N2 < underset69.16H2 < underset34.86O2 KH=144.97,76.48,69.16,34.86 kbar

Q. The value of Henry's law constant for some gases at 293 K is given below. Arrange the gases in the increasing order of their solubility.

He: 144.97 kbar, $H_{2}$ : 69.16 kbar,

$N_{2}$ : 76.48 kbar, $O_{2}$ : 34.86 kbar

$He < N_{2} < H_{2} < O_{2}$

$O_{2} < H_{2} < N_{2} < He$

$H_{2} < N_{2} < O_{2} < He$

$He < O_{2} < N_{2} < H_{2}$

Higher the value of $K_{H}$ , lower is the solubility of gas in the liquid.

The correct order of solubility of these gases is as follows

$144.97 He < 76.48 N_{2} < 69.16 H_{2} < 34.86 O_{2}$

$K_{H} = 144.97, 76.48, 69.16, 34.86 kba r$

Q. The value of Henry's law constant for some gases at 293 K is given below. Arrange the gases in the increasing order of their solubility. He: 144.97 kbar, H2​ : 69.16 kbar, N2​ : 76.48 kbar, O2​ : 34.86 kbar

He<N2​<H2​<O2​

O2​<H2​<N2​<He

H2​<N2​<O2​<He

He<O2​<N2​<H2​