The value of Henry's law constant for argon (Ar), carbon dioxide ( CO 2), methane ( CH 4) and formaldehyde ( HCHO ) are respectively 40.3 K bar, 1.67 K bar, 0.413 K bar and 1.83 × 10-5 K bar at 298 K. The correct order of their solubility is

Question

The value of Henry's law constant for argon (Ar), carbon dioxide ( CO 2), methane ( CH 4) and formaldehyde ( HCHO ) are respectively 40.3 K bar, 1.67 K bar, 0.413 K bar and 1.83 × 10-5 K bar at 298 K. The correct order of their solubility is (A) Ar < CH 4< CO 2< HCHO (B) HCHO < CH 4< CO 2< Ar (C) Ar < CO 2< CH 4< HCHO (D) Ar < CO 2< HCHO < CH 4

Tardigrade Admin · Accepted Answer

Higher the value of Henry's law constant, lower is the solubility of gas in water (or in liquid solvent).
The order of

K_{H}

value is:

40.3 A r > 1.67 C O_{2} > 0.413 C H_{4} > 1.83 \times 1 0^{- 5} H C H O

Thus, the order of solubility is:

A r < C O_{2} < C H_{4} < H C H O

Q. The value of Henry's law constant for argon $(A r)$ , carbon dioxide $(C O_{2})$ , methane $(C H_{4})$ and formaldehyde $(H C H O)$ are respectively $40.3 K$ bar, $1.67 K$ bar, $0.413 K$ bar and $1.83 \times 1 0^{- 5} K$ bar at $298 K$ . The correct order of their solubility is

$A r < C H_{4} < C O_{2} < H C H O$

$H C H O < C H_{4} < C O_{2} < A r$

$A r < C O_{2} < C H_{4} < H C H O$

$A r < C O_{2} < H C H O < C H_{4}$

Higher the value of Henry's law constant, lower is the solubility of gas in water (or in liquid solvent).
The order of $K_{H}$ value is:
$40.3 A r > 1.67 C O_{2} > 0.413 C H_{4} > 1.83 \times 1 0^{- 5} H C H O$
Thus, the order of solubility is:
$A r < C O_{2} < C H_{4} < H C H O$

Q. The value of Henry's law constant for argon (Ar), carbon dioxide (CO2​), methane (CH4​) and formaldehyde (HCHO) are respectively 40.3K bar, 1.67K bar, 0.413K bar and 1.83×10−5K bar at 298K. The correct order of their solubility is

Ar<CH4​<CO2​<HCHO

HCHO<CH4​<CO2​<Ar

Ar<CO2​<CH4​<HCHO

Ar<CO2​<HCHO<CH4​