The value of g on the surface of earth is smallest at the equator because

Question

The value of g on the surface of earth is smallest at the equator because (A) The centripetal force is maximum at equator (B) The centripetal force is least at equator (C) The centrifugal force is maximum at equator (D) The angular speed of earth is least at equator

Tardigrade Admin · Accepted Answer

Due to rotation of earth the effective acceleration due to gravity

g^{'} = g - R ω^{2} co s^{2} λ .

For a given point on the surface of earth

g

decreases as

ω

increases. The angular speed of earth is maximum at equator hence, the value of

g

on the surface of the earth is smallest.

Q. The value of g on the surface of earth is smallest at the equator because

The centripetal force is maximum at equator

The centripetal force is least at equator

The centrifugal force is maximum at equator

The angular speed of earth is least at equator

Due to rotation of earth the effective acceleration due to gravity g′=g−Rω2cos2λ. For a given point on the surface of earth g decreases as ω increases. The angular speed of earth is maximum at equator hence, the value of g on the surface of the earth is smallest.

Q. The value of $g$ on the surface of earth is smallest at the equator because

Due to rotation of earth the effective acceleration due to gravity $g^{'} = g - R ω^{2} co s^{2} λ .$
For a given point on the surface of earth $g$ decreases as $ω$ increases. The angular speed of earth is maximum at equator hence, the value of $g$ on the surface of the earth is smallest.