The value of g at the surface of earth is 9.8 m / s 2. Then the value of ' g ' at a place 480 km above the surface of the earth will be nearly (radius of the earth is 6400 km )

Question

The value of g at the surface of earth is 9.8 m / s 2. Then the value of ' g ' at a place 480 km above the surface of the earth will be nearly (radius of the earth is 6400 km ) (A) 9.8 m / s 2 (B) 7.2 m / s 2 (C) 8.5 m / s 2 (D) 4.2 m / s 2

Tardigrade Admin · Accepted Answer

gh=g[(R/R+h)]2 ⇒ gh=9.8[(6400/6400+480)]=8.48 m / s 2

Q. The value of $g$ at the surface of earth is $9.8 m / s^{2}$ . Then the value of ' $g$ ' at a place $480 km$ above the surface of the earth will be nearly (radius of the earth is $6400 km$ )

$9.8 m / s^{2}$

$7.2 m / s^{2}$

$8.5 m / s^{2}$

$4.2 m / s^{2}$

$g_{h} = g [\frac{R}{R + h}]^{2}$
$\Rightarrow g_{h} = 9.8 [\frac{6400}{6400 + 480}] = 8.48 m / s^{2}$

Q. The value of g at the surface of earth is 9.8m/s2. Then the value of ' g ' at a place 480km above the surface of the earth will be nearly (radius of the earth is 6400km )

9.8m/s2

7.2m/s2

8.5m/s2

4.2m/s2