The value of g at a particular point is 10 ms -2. Suppose the earth shrinks uniformly to half of its present size without losing any mass. The value of g at the same point (assuming that the distance of the point from the centre of the earth does not change) will now be

Question

The value of g at a particular point is 10 ms -2. Suppose the earth shrinks uniformly to half of its present size without losing any mass. The value of g at the same point (assuming that the distance of the point from the centre of the earth does not change) will now be (A) 5 m s -2 (B) 10 m s -2 (C) 3 m s -2 (D) 20 m s -2

Tardigrade Admin · Accepted Answer

F=(G M m) / R2=m g As the mass remains the same and radius, i.e., distance from the centre is also the same, therefore g will remain the same, i.e., 10 m s -2.

Q. The value of $g$ at a particular point is $10 m s^{- 2}$ . Suppose the earth shrinks uniformly to half of its present size without losing any mass. The value of $g$ at the same point (assuming that the distance of the point from the centre of the earth does not change) will now be

$5 m s^{- 2}$

$10 m s^{- 2}$

$3 m s^{- 2}$

$20 m s^{- 2}$

$F = (GM m) / R^{2} = m g$
As the mass remains the same and radius, i.e., distance from the centre is also the same, therefore $g$ will remain the same, i.e., $10 m s^{- 2}$ .

Q. The value of g at a particular point is 10ms−2. Suppose the earth shrinks uniformly to half of its present size without losing any mass. The value of g at the same point (assuming that the distance of the point from the centre of the earth does not change) will now be

5ms−2

10ms−2

3ms−2

20ms−2