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Tardigrade
Question
Physics
The value of Faraday constant is
Q. The value of Faraday constant is
1451
180
Chhattisgarh PMT
Chhattisgarh PMT 2005
Report Error
A
9.65
×
1
0
4
C
B
9.65
×
1
0
4
J
C
6.03
×
1
0
27
J
D
1.6
×
1
0
−
19
C
Solution:
Faraday constant
F
=
N
e
F
=
6.023
×
1
0
23
×
1.6
×
1
0
−
19
C
=
96368
C
=
9.65
×
1
0
4
C