Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
The value of displaystyle∑r=022 22 Cr 23 Cr is
Q. The value of
r
=
0
∑
22
22
C
r
23
C
r
is
3017
126
JEE Main
JEE Main 2023
Binomial Theorem
Report Error
A
45
C
24
0%
B
45
C
23
0%
C
44
C
23
0%
D
44
C
22
100%
Solution:
r
=
0
∑
22
22
C
r
⋅
23
C
r
=
r
=
0
∑
22
22
C
r
⋅
23
C
23
−
r
=
45
C
23