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Tardigrade
Question
Mathematics
The value of Δ =| 5C0 5C3 14 [0.3em] 5C1 5C4 &1 [0.3em] 5C2 5C5 1 | is
Q. The value of
Δ
=
∣
∣
5
C
0
5
C
1
5
C
2
5
C
3
5
C
4
5
C
5
14
1
1
∣
∣
is
2108
212
Determinants
Report Error
A
0
22%
B
-576
42%
C
80
22%
D
none of these
14%
Solution:
Δ
=
∣
∣
5
C
0
5
C
1
5
C
2
5
C
3
5
C
4
5
C
5
14
1
1
∣
∣
Operate
R
1
+
R
2
+
R
3
=
∣
∣
5
C
0
+
5
C
1
+
5
C
2
5
10
5
C
3
+
5
C
4
+
5
C
5
5
1
14
+
1
+
1
1
1
∣
∣
=
∣
∣
16
5
10
16
5
1
16
1
1
∣
∣
=
16
∣
∣
1
5
10
1
5
1
1
1
1
∣
∣
[
∵
5
C
0
+
5
C
1
+
5
C
2
+
5
C
3
+
5
C
4
+
5
C
5
=
16
]
=
∣
∣
1
5
9
1
5
0
1
1
0
∣
∣
=
16
×
9
(
−
4
)
=
−
576