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Tardigrade
Question
Mathematics
The value of cot ( tan -1 π+ tan -1 (1/π))+ tan -1 √3- sec -1(-2) is equal to
Q. The value of
cot
(
tan
−
1
π
+
tan
−
1
π
1
)
+
tan
−
1
3
−
sec
−
1
(
−
2
)
is equal to
61
120
Inverse Trigonometric Functions
Report Error
A
3
−
π
B
3
π
C
3
2
π
D
π
Solution:
cot
(
tan
−
1
π
+
tan
−
1
π
1
)
+
tan
−
1
3
−
sec
−
1
(
−
2
)
=
cot
(
tan
−
1
π
+
cot
−
1
π
)
+
3
π
−
3
2
π
=
cot
(
2
π
)
−
3
π
=
0
−
3
π
=
3
−
π