Question

The value of cot $\frac{\pi }{24}$ is :

• A. $1+\sqrt{2}+\sqrt{3}+\sqrt{6}$
• B. $1-\sqrt{2}+\sqrt{3}+\sqrt{6}$
• C. $2+\sqrt{2}+\sqrt{3}-\sqrt{6}$
• D. $2+\sqrt{2}+\sqrt{3}+\sqrt{6}$

Answer 1

Answer: (D)

Correct answer is (d) $2+\sqrt{2}+\sqrt{3}+\sqrt{6}$