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Mathematics
The value of cot (π/24) is :
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Q. The value of cot $\frac{\pi}{24}$ is :
JEE Main
JEE Main 2020
Trigonometric Functions
A
$1+\sqrt{2}+\sqrt{3}+\sqrt{6}$
B
$1-\sqrt{2}+\sqrt{3}+\sqrt{6}$
C
$2+\sqrt{2}+\sqrt{3}-\sqrt{6}$
D
$2+\sqrt{2}+\sqrt{3}+\sqrt{6}$
Solution:
Correct answer is (d) $2+\sqrt{2}+\sqrt{3}+\sqrt{6}$