The value of cot-1 9 + cosec-1 (√41/4) is given by

Question

The value of cot-1 9 + cosec-1 (√41/4) is given by (A) 0 (B) (π/4) (C) tan-1 2 (D) (π/2)

Tardigrade Admin · Accepted Answer

cot-1 9 + cosec-1 (√41/4) = cot-1 9 + cosec-1 (4/√41) cot-1 9 + cot-1 (5/4) = tan-1 (1/9) + tan-1 (4/5) = tan-1(((1/9)+(4/5)/1-(1)9 ×(4)5) = tan/-1) (1) = (π/4)

Q. The value of $co t^{- 1} 9 + cose c^{- 1} \frac{41}{4}$ is given by

$0$

$\frac{π}{4}$

$t a n^{- 1} 2$

$\frac{π}{2}$

Q. The value of cot−19+cosec−1441​​ is given by

0

4π​

tan−12

2π​

cot−19+cosec−1441​​ =cot−19+cosec−141​4​ cot−19+cot−145​ =tan−191​+tan−154​ =tan−1(1−91​×54​91​+54​​) =tan−1(1)=4π​

Q. The value of $co t^{- 1} 9 + cose c^{- 1} \frac{41}{4}$ is given by

$0$

$\frac{π}{4}$

$t a n^{- 1} 2$

$\frac{π}{2}$