Tardigrade
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Tardigrade
Question
Mathematics
The value of cos2 θ + sec2 θ is always
Q. The value of
co
s
2
θ
+
se
c
2
θ
is always
1743
225
Report Error
A
less than 1
0%
B
equal to 1
0%
C
greater than 1, but less than 2
0%
D
greater than or equal to 2.
100%
Solution:
co
s
2
θ
+
se
c
2
θ
=
(
cos
θ
−
sec
θ
)
2
+
2
>
2