∣∣10C411C612C810C511C712C911Cm12Cm+213Cm+4∣∣=0 Applying R2→R1+R2⇒∣∣10C4+10C511C6+11C712C8+12C910C511C712C911Cm12Cm+213Cm+4∣∣=0⇒∣∣11C512C713C910C511C712C911Cm12Cm+213Cm+4∣∣=0 It means either two rows or two columns are identical ∴11C5=11Cm,12C7=12Cm+2,13C4=13Cm+4⇒m=5