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Tardigrade
Question
Mathematics
The value of | beginmatrix 12 22 32 22 32 42 32 42 52 endmatrix | is:
Q. The value of
∣
∣
1
2
2
2
3
2
2
2
3
2
4
2
3
2
4
2
5
2
∣
∣
is:
2207
224
KEAM
KEAM 2001
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A
8
B
−
8
C
400
D
1
E
0
Solution:
∣
∣
1
2
2
2
3
2
2
2
3
2
4
2
3
2
4
2
5
2
∣
∣
=
∣
∣
1
4
9
4
9
16
9
16
25
∣
∣
=
∣
∣
1
4
9
3
5
7
5
7
9
∣
∣
C
2
→
C
2
−
C
1
an
d
C
3
→
C
3
−
C
2
=
∣
∣
1
4
9
3
5
7
2
2
2
∣
∣
C
3
→
C
3
−
C
2
=
∣
∣
1
3
5
3
2
2
2
0
0
∣
∣
R
2
→
R
2
−
R
1
R
3
→
R
3
−
R
2
=
2
∣
∣
3
5
2
2
∣
∣
=
2
(
6
−
10
)
=
−
8