The value of acceleration due to gravity at a depth of 1600 km is equal to

Question

The value of acceleration due to gravity at a depth of 1600 km is equal to (A) 9.8 ms-2 (B) 4.9 ms-2 (C) 19.6 ms-2 (D) 7.35 ms-2

Tardigrade Admin · Accepted Answer

Given. Depth (d)=1600 km We know that, gd =g(1-(d/R)) Here g=9.8 m / s 2 R=6400 km gd =g(1-(1600/6400)) =9.8(1-(1/4)) =9.8((4-1/4))=(9.8 × 3/4) gd =7.35 ms -2

Q. The value of acceleration due to gravity at a depth of $1600 km$ is equal to

$9.8 m s^{- 2}$

$4.9 m s^{- 2}$

$19.6 m s^{- 2}$

$7.35 m s^{- 2}$

Given.
Depth $(d) = 1600 km$
We know that,
$g_{d} = g (1 - \frac{d}{R})$
Here $g = 9.8 m / s^{2}$
$R = 6400 km$
$g_{d} = g (1 - \frac{1600}{6400})$
$= 9.8 (1 - \frac{1}{4})$
$= 9.8 (\frac{4 - 1}{4}) = \frac{9.8 \times 3}{4}$
$g_{d} = 7.35 m s^{- 2}$

Q. The value of acceleration due to gravity at a depth of 1600km is equal to

9.8ms−2

4.9ms−2

19.6ms−2

7.35ms−2