Question

The value of (64) ${}^{\left(\frac{1}{{\log }_{9}16}\right)}+\left({\log }_{5}4\cdot {\log }_{6}5\cdot {\log }_{7}6\right)-{\log }_{7}28$ is equal to

• A. 26
• B. 27
• C. 28
• D. 30

Answer 1

Answer: (A)

$(64{)}^{{\log }_{16}9}+{\log }_{7}4-{\log }_{7}28$
$=4^{3{\log }_{4}3}+{\log }_7\left(\frac{4}{28}\right)$
$=27-1=26$