Question

The value of $2{\cot }^2(\frac{\pi }{6})+4{\tan }^2(\frac{\pi }{6})$ $-3\text{cosec }\frac{\pi }{6}$ is

• A. $2$
• B. $4$
• C. $\frac{4}{3}$
• D. $\frac{3}{4}$

Answer 1

Answer: (C)

$2{\cot }^2\left(\frac{\pi }{6}\right)+4{\tan }^2\left(\frac{\pi }{6}\right)-3\text{cosec}\frac{\pi }{6}$
$=2{(\sqrt{3})}^2+4{\left(\frac{1}{\sqrt{3}}\right)}^2-3(2)=2\times 3+\frac{4}{3}-6=\frac{4}{3}$