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Tardigrade
Question
Mathematics
The value of √2( cos 15°- sin 15°) is equal to
Q. The value of
2
(
cos
1
5
∘
−
sin
1
5
∘
)
is equal to
1611
210
KEAM
KEAM 2012
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A
3
B
2
C
1
D
2
E
2
3
Solution:
2
(
cos
1
5
∘
−
sin
1
5
∘
)
=
2
(
2
1
cos
1
5
∘
−
2
1
sin
1
5
∘
)
×
2
=
2
(
sin
4
5
∘
cos
1
5
∘
−
cos
4
5
∘
sin
1
5
∘
)
=
2
sin
(
4
5
∘
−
1
5
∘
)
=
2
sin
3
0
∘
=
2
×
2
1
=
1