Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
The value of |2 3 3 7|+|1 2 3 7|+|(1/2) (4/3) 3 7|+|(1/22) (8/32) 3 7|+ ldots ldots ∞ is equal to
Q. The value of
∣
∣
2
3
3
7
∣
∣
+
∣
∣
1
3
2
7
∣
∣
+
∣
∣
2
1
3
3
4
7
∣
∣
+
∣
∣
2
2
1
3
3
2
8
7
∣
∣
+
……
∞
is equal to
139
77
Determinants
Report Error
A
13
B
5
C
2
−
13
D
1
Solution:
∣
∣
2
+
1
+
2
1
+
2
2
1
+
……
∞
3
3
+
2
+
3
4
+
……
∞
7
∣
∣
=
∣
∣
1
−
2
1
2
3
1
−
3
2
3
7
∣
∣
=
∣
∣
4
3
9
7
∣
∣
=
28
−
27
=
1