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Question
Mathematics
The value of (1/√10-√9)-(1/√11-√10)+(1/√12-√11) -....-(1/√121-√120) is equal to
Q. The value of
10
−
9
1
−
11
−
10
1
+
12
−
11
1
−
....
−
121
−
120
1
is equal to
3269
199
KEAM
KEAM 2010
Sequences and Series
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A
−
10
B
11
C
14
D
13
E
−
8
Solution:
We have
10
−
9
1
−
11
−
10
1
+
12
−
11
1
−
....
−
121
−
120
1
=
10
+
9
−
11
−
10
+
12
+
11
−
.....
−
121
−
120
=
9
−
121
=
3
−
11
=
−
8