Question

The valency of carbon is generally 4 , but its oxidation state may be $-4,-2,0,+2,-1$, etc. In the compounds containing $C,H$, and $O$, the oxidation number of $C$ is calculated as Oxidation number of $C=\frac{2n_O-n_H}{n_C}$
Where $n_0,n_H$, and $n_C$ are the number of oxygen, hydrogen and carbon atoms , respectively
The oxidation state of $C$ in diamond is

• A. $0$
• B. $+1$
• C. $-1$
• D. $+2$

Answer 1

Answer: (A)

Carbon in diamond is in elemental state, so the oxidation state of $C$ in diamond is zero