1. Tardigrade
  2. Question
  3. Chemistry
  4. The valency of carbon is generally 4 , but its oxidation state may be -4,-2,0,+2,-1, etc. In the compounds containing C , H, and O, the oxidation number of C is calculated as Oxidation number of C =(2 n O -n H /n C ) Where n0, n H , and n C are the number of oxygen, hydrogen and carbon atoms , respectively The oxidation state of C in diamond is

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Q. The valency of carbon is generally 4 , but its oxidation state may be $-4,-2,0,+2,-1$, etc. In the compounds containing $C , H$, and $O$, the oxidation number of $C$ is calculated as Oxidation number of $C =\frac{2 n_{ O }-n_{ H }}{n_{ C }}$
Where $n_0, n_{ H }$, and $n_{ C }$ are the number of oxygen, hydrogen and carbon atoms , respectively
The oxidation state of $C$ in diamond is

Redox Reactions

Solution:

Carbon in diamond is in elemental state, so the oxidation state of $C$ in diamond is zero