Q. The unit of thermal conductance is

1170 276 Uttarkhand PMTUttarkhand PMT 2008 Report Error

A

$W K^{- 1}$

B

$J K^{- 1}$

C

$W K$

D

$J K$

Solution:

Thermal conductance $= \frac{Δ Q}{t Δ θ}$
$= \frac{J}{sK}$
$= \frac{J}{s} K^{- 1}$
$= W K^{- 1}$