The unit of rate constant for a zero order reaction is

Question

The unit of rate constant for a zero order reaction is (A)  s-1  (B) L mol-1 s-1 (C)  mol L-1s-1  (D) L2 mol-2 s-1

Tardigrade Admin · Accepted Answer

For nth order of reaction a general formula for the unit of rate constant is (( text mole / text litre ))1-n × sec -1 ∵ For zero order reaction, n=0 ∴ Unit of rate constant for zero order reaction is mole textlitre-1 sec -1 or mol L-1 S-1.

Q. The unit of rate constant for a zero order reaction is

$s^{- 1}$

$L m o l^{- 1} s^{- 1}$

$m o l L^{- 1} s^{- 1}$

$L^{2} m o l^{- 2} s^{- 1}$

For $n^{t h}$ order of reaction a general formula for the unit of rate constant is $(\frac{mole}{litre})^{1 - n} \times sec^{- 1}$
$∵$ For zero order reaction, $n = 0$
$∴$ Unit of rate constant for zero order reaction is mole $litre^{- 1} sec^{- 1}$ or $m o l L^{- 1} S^{- 1}$ .

Q. The unit of rate constant for a zero order reaction is

s−1

Lmol−1s−1

molL−1s−1

L2mol−2s−1

For nth order of reaction a general formula for the unit of rate constant is ( litre mole ​)1−n×sec−1 ∵ For zero order reaction, n=0 ∴ Unit of rate constant for zero order reaction is mole litre−1sec−1 or molL−1S−1.

$s^{- 1}$

$L m o l^{- 1} s^{- 1}$

$m o l L^{- 1} s^{- 1}$

$L^{2} m o l^{- 2} s^{- 1}$

For $n^{t h}$ order of reaction a general formula for the unit of rate constant is $(\frac{mole}{litre})^{1 - n} \times sec^{- 1}$
$∵$ For zero order reaction, $n = 0$
$∴$ Unit of rate constant for zero order reaction is mole $litre^{- 1} sec^{- 1}$ or $m o l L^{- 1} S^{- 1}$ .