The unit in which the solubility product of barium phosphate is expressed as

Question

The unit in which the solubility product of barium phosphate is expressed as (A) mol2 dm -6 (B) mol3 dm-9 (C) mol4 dm-12 (D) mol5 dm-15

Tardigrade Admin · Accepted Answer

Barium phosphate when dissolved in water: Ba3(PO4)2 arrow 3Ba2++2PO43- Let the solubility of Ba 3 (PO4)2 be s mol dm-3 ⇒ Solubility product = (Ba2+)3 (PO4-3)2 s5 = mol5 dm-15

Q. The unit in which the solubility product of barium phosphate is expressed as

$m o l^{2} d m^{- 6}$

$m o l^{3} d m^{- 9}$

$m o l^{4} d m^{- 12}$

$m o l^{5} d m^{- 15}$

Barium phosphate when dissolved in water:
$B a_{3} (P O_{4})_{2} \to 3 B a^{2 +} + 2 P O_{4}^{3 -}$
Let the solubility of Ba 3 (PO₄)₂ be s mol dm^-3
$\Rightarrow$ Solubility product = (Ba²⁺)³ (PO₄^-3)²
s⁵ = mol⁵ dm^-15

Q. The unit in which the solubility product of barium phosphate is expressed as

mol2dm−6

mol3dm−9

mol4dm−12

mol5dm−15

Barium phosphate when dissolved in water: Ba3​(PO4​)2​→3Ba2++2PO43−​ Let the solubility of Ba 3 (PO4)2 be s mol dm-3 ⇒ Solubility product = (Ba2+)3 (PO4-3)2 s5 = mol5 dm-15

$m o l^{2} d m^{- 6}$

$m o l^{3} d m^{- 9}$

$m o l^{4} d m^{- 12}$

$m o l^{5} d m^{- 15}$

Barium phosphate when dissolved in water:
$B a_{3} (P O_{4})_{2} \to 3 B a^{2 +} + 2 P O_{4}^{3 -}$
Let the solubility of Ba 3 (PO₄)₂ be s mol dm^-3
$\Rightarrow$ Solubility product = (Ba²⁺)³ (PO₄^-3)²
s⁵ = mol⁵ dm^-15