The unit cell dimensions of a cubic lattice (edges a, b, c and the angles between them, α, β and γ) are

Question

The unit cell dimensions of a cubic lattice (edges a, b, c and the angles between them, α, β and &gamma;) are (A) a = b = c, α = β = &gamma; = 900 (B) a = b ≠ c, α = β = &gamma; = 900 (C) a = b = c,α = &gamma; = 900, β ≠ 900 (D) a ≠ b ≠ c,a = b = 900, &gamma; ≠ 900

Tardigrade Admin · Accepted Answer

It is based on the definition of the cubic lattice.

Q. The unit cell dimensions of a cubic lattice (edges a, b, c and the angles between them, $α, β$ and $γ$ ) are

$a = b = c, α = β = γ = 9 0^{0}$

$a = b \neq = c, α = β = γ = 9 0^{0}$

$a = b = c, α = γ = 9 0^{0}, β \neq = 9 0^{0}$

$a \neq = b \neq = c, a = b = 9 0^{0}, γ \neq = 9 0^{0}$

It is based on the definition of the cubic lattice.

Q. The unit cell dimensions of a cubic lattice (edges a, b, c and the angles between them, α,β and γ) are

a=b=c,α=β=γ=900

a=b=c,α=β=γ=900

a=b=c,α=γ=900,β=900

a=b=c,a=b=900,γ=900

It is based on the definition of the cubic lattice.

Q. The unit cell dimensions of a cubic lattice (edges a, b, c and the angles between them, $α, β$ and $γ$ ) are

$a = b = c, α = β = γ = 9 0^{0}$

$a = b \neq = c, α = β = γ = 9 0^{0}$

$a = b = c, α = γ = 9 0^{0}, β \neq = 9 0^{0}$

$a \neq = b \neq = c, a = b = 9 0^{0}, γ \neq = 9 0^{0}$