The uncertainty in position and velocity of the particle are 0.1 nm and 5.27 ×10-27 ms-1 respectively. Then the mass of the particle is: (h = 6.625 × 10-34 Js)

Question

The uncertainty in position and velocity of the particle are 0.1 nm and 5.27 ×10-27 ms-1 respectively. Then the mass of the particle is: (h = 6.625 × 10-34 Js) (A) 200 g (B) 300 g (C) 100 g (D) 1000 g

Tardigrade Admin · Accepted Answer

Δ x =0.1 ×10-9 m. Δ V =5.27×10-27 ms-1 ∴ Δ x × mΔ V =(h/4π) ∴ 0.1 ×10-9 × m×5.27 ×10-27=0.57 ×10-34 ∴ m=0.1 kg.=100g.

Q. The uncertainty in position and velocity of the particle are $0.1 nm$ and $5.27 \times 1 0^{- 27} m s^{- 1}$ respectively. Then the mass of the particle is: $(h = 6.625 \times 1 0^{- 34} J s)$

$200 g$

$300 g$

$100 g$

$1000 g$

$Δ x = 0.1 \times 1 0^{- 9} m .$
$Δ V = 5.27 \times 1 0^{- 27} m s^{- 1}$
$∴ Δ x \times m Δ V = \frac{h}{4 π}$
$∴ 0.1 \times 1 0^{- 9} \times m \times 5.27 \times 1 0^{- 27} = 0.57 \times 1 0^{- 34}$
$∴ m = 0.1 k g . = 100 g .$

Q. The uncertainty in position and velocity of the particle are 0.1nm and 5.27×10−27ms−1 respectively. Then the mass of the particle is: (h=6.625×10−34Js)

200g

300g

100g

1000g