Question

The uncertainty in position and velocity of the particle are $0.1\, nm$ and $5.27 \times10^{-27} ms^{-1}$ respectively. Then the mass of the particle is: $(h = 6.625 \times 10^{-34} Js)$

• A. $200\, g$
• B. $300\, g$
• C. $100\, g$
• D. $1000\, g$

Answer 1

Answer: (C)

$\Delta x =0.1 \times10^{-9} m.$
$\Delta V =5.27\times10^{-27} ms^{-1} $
$\therefore \Delta x \times m\Delta V =\frac{h}{4\pi} $
$ \therefore 0.1 \times10^{-9} \times m\times5.27 \times10^{-27}=0.57 \times10^{-34}$
$\therefore m=0.1 kg.=100g.$