Question

The types of hybridisation on the five carbon atoms from left to right in the molecule CH${}_3-CH=C=CH-C{H}_3$ are

• A. $s{p}^3,s{p}^2,s{p}^2,s{p}^2,s{p}^3$
• B. $s{p}^3,sp,s{p}^2,s{p}^2,s{p}^3$
• C. $s{p}^3,s{p}^2,sp,s{p}^2,s{p}^3$
• D. $s{p}^3,s{p}^2,s{p}^2,sp,s{p}^3$
• E. $s{p}^3,sp,sp,s{p}^2,s{p}^3$

Answer 1

Answer: (C)

Number of hybrid orbitals= number of $\sigma$-bonds formed.